Which ion forms a yellow precipitate with silver nitrate?

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Multiple Choice

Which ion forms a yellow precipitate with silver nitrate?

Explanation:
Silver nitrate tests for halide ions by forming insoluble silver halides, and the color of the precipitate reveals which halide is present. When iodide is present, silver iodide forms and appears yellow because AgI is a very insoluble solid with that characteristic color. Chloride would give a white precipitate (silver chloride), while sulfate forms a white solid (silver sulfate) and nitrate typically stays in solution with no visible precipitate. So the yellow precipitate points to iodide.

Silver nitrate tests for halide ions by forming insoluble silver halides, and the color of the precipitate reveals which halide is present. When iodide is present, silver iodide forms and appears yellow because AgI is a very insoluble solid with that characteristic color. Chloride would give a white precipitate (silver chloride), while sulfate forms a white solid (silver sulfate) and nitrate typically stays in solution with no visible precipitate. So the yellow precipitate points to iodide.

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